(2x^2-5)/(5x^2)=0

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Solution for (2x^2-5)/(5x^2)=0 equation: 


D( x )

5*x^2 = 0

5*x^2 = 0

5*x^2 = 0

5*x^2 = 0 // : 5

x^2 = 0

x = 0

x in (-oo:0) U (0:+oo)

(2*x^2-5)/(5*x^2) = 0

2*x^2 = 5 // : 2

x^2 = 5/2

x^2 = 5/2 // ^ 1/2

abs(x) = (5/2)^(1/2)

x = (5/2)^(1/2) or x = -(5/2)^(1/2)

x in { (5/2)^(1/2), -(5/2)^(1/2) }

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